Does anyone know how to find the standard deviation from a set of scores. I am really confused by this.

I'm stretching to remember this...Alice, help...it is tedious: First, find the mean for the set. For each value (x) in your set, subtract the overall mean from x, then multiply that result by itself (otherwise known as determining the square of that value). Add up all those squared values. Then divide that result by the number of values in the set, minus 1 (n-1). Then, find the square root of that last number. Or, you could just enter the values into Excel, and use the STDEV or STDEVP formula, which would be a lot easier! Or, you could get yourself a good scientific calculator!

You did well kc!!! Here's a site that explains with an example: http://easycalculation.com/statistics/learn-standard-deviation.php "Formula: Standard Deviation Population Standard Deviation (OOPS, IT'S NOT SHOWING THE FORMULA!!) where Σ = Sum of X = Individual score M = Mean of all scores N = Sample size (Number of scores) Variance : Variance = s2 Standard Deviation Method1 Example: To find the Standard deviation of 1,2,3,4,5. Step 1: Calculate the mean and deviation. X M (X-M) (X-M)2 1 3 -2 4 2 3 -1 1 3 3 0 0 4 3 1 1 5 3 2 4 Step 2:Find the sum of (X-M)2 4+1+0+1+4 = 10 Step 3:N = 5, the total number of values.Find N-1. 5-1 = 4 Step 4:Now find Standard Deviation using the formula. √10/√4 = 1.58113 Standard Deviation Method2 Example: To find the Standard deviation of 1,2,3,4,5. Step 1:First, square each of the scores. X X2 1 1 2 4 3 9 4 16 5 25 Step2: Use the formula s = square root of[(sum of Xsquared -((sum of X)*(sum of X)/N))/(N-1)] = square root of[(55-((15)*(15)/5))/(5-1)] = square root of[(55-(225/5))/4] = square root of[(55-45)/4] = square root of[10/4] = square root of[2.5] s = 1.58113"