Discussion in 'Secondary Education' started by Peachyness, Dec 15, 2009.
Dec 15, 2009
okay, that didn't come out well.
I know you need to do the u substitution.
so, u=x+3, but du=dx, right? So, what do I do with the x in front of the (x+3)??
It'a a little hard to read; are you integratng (x+3) to the one half??
If so, isn't it (x+3) to the 3/2, times 2/3?? I think that, as long as it's one x to the first, it's pretty straight forward.
That said, I haven't touched calc since 2000, so check my work!
Sorry Peachy, I misread the question and now have a feverish child in my lap as I type; I'm of no help to you tonight!
If u=x + 3, then x = u-3, right? You can back substitute and get
(u -3)u^1/2, then multiply though to get u^3/2 -3u^1/2, which you can easily integrate with the power rule.
Let's try this again:
Didn't work. Did you understand what I typed. Math characters are so hard to type on this forum..
you must have posted when I was trying to get this to work. Someone posted a thread on how to do this but, I can't get it to work.... oh well. OKay, I'm going to work out the problem based on what you wrote and see if I can "get it". Thanks!
OOOOOOOOOOOOOOOOOOOOOOOOHHHHHHHH, I got it! Thanks!!!
You're welcome. Don't forget that the solution to most of these 'tricky" problems is usually some sort of simple manipulation. Students get so caught up in the problem being "hard" that they forget to look at the simple things.
Yeah, no kidding! Man, that really was so simple, and yet I spent so long staring at that problem.... tsk tsk... thanks!
Sorry I was of no help; I had to strip a bed and get Julia all settled.
Oh, Alice, that is all right! I know you're a super busy mom.
Peachy, if you haven't got one, you might want copies of either of these:
Calculus for Cats, by Amdahl and Loats
Misteaks, and How to Find Them Before the Teacher Does, 3d ed., by Barry Cipra
Dec 16, 2009
Are you sure you just spoke English?
You can also use integration by parts (if you know how to do that)...though what mmswm did will work just fine.
I thought about using parts, but it was easier to substitute...at least is was easier to explain on this forum that way. I find that there's rarely only one way to attack a problem. The other reason I went with the way I did is because I wasn't sure what course the OP is taking. I know we didnt' introduce by parts unti Calc2, though there was some simple integration at the end of calc1.
I'm betting that the OP has not done integration by parts (based on the type of question asked), but I thought I'd throw out the idea anyway.
I thought about going through a power series solution, but then figured that might be a little overkill
Remember, we want people to LIKE math. Overwhelming people usually isn't the best way to do that :lol:
One can do worse, mm, than to paraphrase E.B. White's remark on William Strunk's goal in writing The Elements of Style:
"Will felt that the reader/math student was in serious trouble most of the time, floundering in a swamp, and that it was the duty of anyone attempting to write English/teach math to drain this swamp quickly and get the reader/student up on dry ground or at least to throw a rope.”
But that is the kind of stuff that made me like math
Yeah, it was linear algebra that did it for me, but, most people would consider too much information frightening.
Bob the farmer has a 20 by 50 field. What is the area of his field?
Simple........f(x) = 20 and then integrate f(y) = 20dY from 0 to 50.
What's not fun about that?
OK, since no one has posted an answer yet... (grrr!)
Is it ((2(x+3)^(5/2))/5)-(x+3)^(3/2) ???
Help me, I'm rusty!
Almost, but not quite. The last term should be -((x+3)^(3/2))/2
I think it should be
also don't forget your arbitrary constant
You're right. I haven't been to sleep since 5pm yesterday (it's 7pm now). Serves me right to try to do mental math, while watching mythbusters with my boys and eating chocolate chip cookie dough and surfing the net...all at the same time. Particularly when I'm this tired.
I need to bookmark that link.
yes...it is very nice!
Drat. It's not a link. It's code. Is there a site that provides the code where one could cut and paste?
here is a pdf with a lot of commands
Which presupposes that one has LaTEX on one's computer, yes?
Just type in the LaTeX command after
then display as an image...
What, like in a regular ol' browser window??
yes you can do that.
Separate names with a comma.